The paint in a certain container is sufficient to paint an area equal to $ 9.375 \mathrm{~m}^{2} $. How many bricks of dimensions $ 22.5 \mathrm{~cm} \times 10 \mathrm{~cm} \times 7.5 \mathrm{~cm} $ can be painted out of this container?
Given:
The paint in a certain container is sufficient to paint an area equal to $9.375\ m^2$.
The dimensions of each brick is $22.5\ cm \times 10\ cm \times 7.5\ cm$.
To do:
We have to find the number of bricks that can be painted out of the container.
Solution:
Area of the place for painting $= 9.375\ m^2$
Dimension of each brick $= 22.5\ cm \times 10\ cm \times 7.5\ cm$
Therefore,
Surface area of each brick $= 2 (lb + bh + lh)$
$= 2(22.5 \times 10 + 10 \times 7.5 + 7.5 \times 22.5)$
$= 2(225 + 75 + 168.75)$
$= 2 \times 468.75$
$= 937.5\ cm^2$
This implies,
Number of bricks that can be painted $=\frac{\text { Total area }}{\text { Area of one brick }}$
$=\frac{9.375 \times 100 \times 100}{937.5}$
$=\frac{937.5 \times 100}{937.5}$
$=100$ bricks
Therefore, the number of bricks that can be painted out of the container is $100$ bricks.
Related Articles
- The paint in a certain container is sufficient to paint on area equal to $9.375\ m^2$. How many bricks of dimension $22.5\ cm \times 10\ cm \times 7.5\ cm$ can be painted out of this container?
- The paint in the container os sufficient to paint an area of 9.375m^2. How many bricks of dimensions 22.5cm X 10cm X 7.5cm can be painted out of this container
- A cistern, internally measuring \( 150 \mathrm{~cm} \times 120 \mathrm{~cm} \times 110 \mathrm{~cm} \), has \( 129600 \mathrm{~cm}^{3} \) of water in it. Porous bricks are placed in the water until the cistern is full to the brim. Each brick absorbs one-seventeenth of its own volume of water. How many bricks can be put in without overflowing the water, each brick being \( 22.5 \mathrm{~cm} \times 7.5 \mathrm{~cm} \times 6.5 \mathrm{~cm} \) ?
- How many coins \( 1.75 \mathrm{~cm} \) in diameter and \( 2 \mathrm{~mm} \) thick must be melted to form a cuboid \( 11 \mathrm{~cm} \times 10 \mathrm{~cm} \times 7 \mathrm{~cm} ? \)
- Find the length of the longest rod that can be put in the room of dimensions \( 10 \mathrm{~cm} \times 6 \mathrm{~cm} \) \( \times 4 \mathrm{~cm} . \quad \)
- How many spherical lead shots each of diameter \( 4.2 \mathrm{~cm} \) can be obtained from a solid rectangular lead piece with dimensions \( 66 \mathrm{~cm} \times 42 \mathrm{~cm} \times 21 \mathrm{~cm} \).
- Find the volume of the cuboid having the following dimensions.\( 12 \mathrm{cm} \times 5 \mathrm{cm} \times 8 \mathrm{cm} \).
- Find the area of a quadrilateral \( \mathrm{ABCD} \) in which \( \mathrm{AB}=3 \mathrm{~cm}, \mathrm{BC}=4 \mathrm{~cm}, \mathrm{CD}=4 \mathrm{~cm} \), \( \mathrm{DA}=5 \mathrm{~cm} \) and \( \mathrm{AC}=5 \mathrm{~cm} \).
- A matchbox measures \( 4 \mathrm{~cm} \times 2.5 \mathrm{~cm} \times 1.5 \mathrm{~cm} \). What will be the volume of a packet containing 12 such boxes?
- Shanti Sweets Stall was placing an order for making cardboard boxes for packing their sweets. Two sizes of boxes were required. The bigger of dimensions \( 25 \mathrm{~cm} \times 20 \mathrm{~cm} \times 5 \mathrm{~cm} \) and the smaller of dimensions \( 15 \mathrm{~cm} \times 12 \mathrm{~cm} \times 5 \mathrm{~cm} \). For all the overlaps, \( 5 \% \) of the total surface area is required extra. If the cost of the cardboard is \( Rs.\ 4 \) for \( 1000 \mathrm{~cm}^{2} \), find the cost of cardboard required for supplying 250 boxes of each kind.
- 16 glass spheres each of radius \( 2 \mathrm{~cm} \) are packed into a cuboidal box of internal dimensions \( 16 \mathrm{~cm} \times 8 \mathrm{~cm} \times 8 \mathrm{~cm} \) and then the box is filled with water. Find the volume of water filled in the box.
- Find the areas of the rectangles whose sides are :(a) \( 3 \mathrm{~cm} \) and \( 4 \mathrm{~cm} \)(b) \( 12 \mathrm{~m} \) and \( 21 \mathrm{~m} \)(c) \( 2 \mathrm{~km} \) and \( 3 \mathrm{~km} \)(d) \( 2 \mathrm{~m} \) and \( 70 \mathrm{~cm} \)
- To stitch a shirt, \( 2 \mathrm{~m} 15 \mathrm{~cm} \) cloth is needed. Out of \( 40 \mathrm{~m} \) cloth, how many shirts can be stitched and how much cloth will remain?(Hint: convert data in cm.)
Kickstart Your Career
Get certified by completing the course
Get Started