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Suppose 2 kg of sugar contains 9×10 raised to 6 crystals. How many sugar crystals are there in (i) 5kg of sugar (ii) 1.2 kg of sugar ?
Given: 2kg of sugar contains $9\times10^6$ crystals
To find :
I) how many sugar crystals in 5k sugar
ii) how many crystals in 1.2kg of sugar
Solution
Crystals in 2 kg of sugar = $9\times10^6$
Crystals in 1 kg of sugar = $\frac{9}{2} \times10^6$
i)Crystals in 5 kg of sugar = $ 5 \times \frac{9}{2} \times10^6$
= $\frac{45}{2} \times10^6$
= 22.5 $\times10^6$
Crystals in 5 kg of sugar = 22.5 $\times10^6$
ii) Crystals in 1.2 kg of sugar = 1.2 $\times \frac{9}{2} \times10^6$
= $\frac{10.8}{2} \times 10^6$
= $5.4 \times 10^6$
Crystals in 1.2 kg of sugar = $5.4 \times 10^6$