A sugar syrup of mass 214.2g contains 34.2g of sugar. Calculate the concentration of sugar in the syrup.

Mass of syrup = 214.2g                               (given)

Mass of sugar in syrup= 34.2g                 (given)                  

Mass of water in syrup  =  Mass of syrup - Mass of sugar in syrup

                       = 242.2 - 34.2 =180g

The molecular formula of sugar is C₁₂H₂₂O_11.

Molecular mass of sugar = 12(mass of C) + 22(mass of H) + 11(mass of O)

         = C₁₂H₂₂O₁₁ = 12(12.01) + 22(1.008) + 11(16.00)

                 = C₁₂H₂₂O₁₁ = 342.30 

The molar mass of sugar ⇒ 342 g/mol         (rounding off 342.30)

No. of moles of sugar (nA)  = 34.2 ÷ 342 = 0.1mole

No. of moles of water (nB) = 180 ÷ 18 = 10 moles

Molarity =0.1 × 1000 ÷ 180 = 0.56 mole

Mole fraction of sugar  =  nA ÷  (nA + nB)

                                   = 0.1 ÷ (0.1 + 10) = 0.009

Thus, the mole fraction of sugar syrup is 0.009.

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Updated on: 10-Oct-2022

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