Suppose $ 2 \mathrm{~kg} $ of sugar contains $ 9 \times $ $ 10^{6} $ crystals. How many sugar crystals are there in
(i) $ 5 \mathrm{~kg} $ of sugar?
(ii) $ 1.2 \mathrm{~kg} $ of sugar?

Given:

\( 2 \mathrm{~kg} \) of sugar contains \( 9 \times \) \( 10^{6} \) crystals.
To do:

We have to find the number of sugar crystals in
(i) \( 5 \mathrm{~kg} \) of sugar
(ii) \( 1.2 \mathrm{~kg} \) of sugar
Solution:

Number of crystals in 2 kg of sugar $=9\times10^6$

This implies,

Number of crystals in 1 kg of sugar $=\frac{9\times10^6}{2}$

Therefore,

(i) Number of crystals in 5 kg of sugar $=5\times\frac{9\times10^6}{2}=\frac{45\times10^6}{2}=22.5\times10^6$.

(ii) Number of crystals in 1.2 kg of sugar $=1.2\times\frac{9\times10^6}{2}=0.6\times9\times10^6=5.4\times10^6$.

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Updated on: 10-Oct-2022

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