Simplify the following:$(\frac{22}{7})^{-4} \times(\frac{7}{44})^{-4}$.

Given :

The given expression is $(\frac{22}{7})^{-4} \times(\frac{7}{44})^{-4}$.

To do :

We have to simplify the given expression.

Solution :

$(\frac{22}{7})^{-4} \times(\frac{7}{44})^{-4}$

$\Rightarrow (\frac{22}{7} \times \frac{7}{44})^{-4}$       $[a^m \times b^m=(a\times b)^m]$

$\Rightarrow (\frac{1}{2})^{-4}$

$\Rightarrow (2)^4$              $[a^{-m}=(\frac{1}{a})^m]$

$\Rightarrow 2 \times 2\times 2 \times 2 = 16$

Therefore, the value of $(\frac{22}{7})^{-4} \times(\frac{7}{44})^{-4}$ is 16.

$\left(\frac{22}{7}\right)^{-4} \times \left(\frac{7}{44}\right)^{-4}$

Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

31 Views

Kickstart Your Career

Get certified by completing the course

Get Started