Solve the following
$ \frac{-4}{7}+\frac{7}{6}+\frac{2}{7}+3+\frac{(-11)}{6} $

Given: $ \frac{-4}{7}+\frac{7}{6}+\frac{2}{7}+3+\frac{(-11)}{6} $

To do:  Find the value of the expression given.

Solution:

$ \frac{-4}{7}+\frac{7}{6}+\frac{2}{7}+3+\frac{(-11)}{6} $

$ \frac{-4}{7}+\frac{2}{7}+\frac{7}{6}-\frac{11}{6}+3 $

$ \frac{-2}{7}+\frac{-4}{6}+3 $

$\frac{-2\times6-4\times7+3\times42}{42}$

$\frac{-12-28+126}{42}$

$\frac{-40+128}{42}$

$\frac{88}{42}$

$\frac{44}{21}$

Therefore, the value of given expression is $\frac{44}{21}$

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Updated on: 10-Oct-2022

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