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Show that the following sets of points are collinear.$(2, 5), (4, 6)$ and $(8, 8)$
Given:
Given vertices are $(2, 5), (4, 6)$ and $(8, 8)$.
To do:
We have to show that the given points are collinear.
Solution:
Let $A (2, 5), B (4, 6)$ and $C (8, 8)$ be the vertices of a triangle $ABC$.
We know that,
Three points are collinear if the area of the triangle formed by them is zero.
Area of a triangle with vertices $(x_1,y_1), (x_2,y_2), (x_3,y_3)$ is given by,
Area of $\Delta=\frac{1}{2}[x_{1}(y_{2}-y_{3})+x_{2}(y_{3}-y_{1})+x_{3}(y_{1}-y_{2})]$
Therefore,
Area of \( \Delta \mathrm{ABC}=\frac{1}{2}[2(6-8)+4(8-5)+8(5-6)] \)
\( =\frac{1}{2} [2 \times(-2)+4 \times 3+8 \times(-1)] \)
\( =\frac{1}{2}[-4+12-8] \)
\( =\frac{1}{2} \times 0 \)
\( =0 \)
Here,
Area of \( \Delta \mathrm{ABC}=0 \)
Therefore, points \( \mathrm{A}, \mathrm{B} \) and \( \mathrm{C} \) are collinear.
Hence proved.
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