Show that the following sets of points are collinear.$(1, -1), (2, 1)$ and $(4, 5)$


Given:

Given vertices are $(1, -1), (2, 1)$ and $(4, 5)$.

To do:

We have to show that the given points are collinear.

Solution:

Let $A (1, -1), B (2, 1)$ and $C (4, 5)$ be the vertices of a triangle $ABC$.

We know that,

Three points are collinear if the area of the triangle formed by them is zero.

Area of a triangle with vertices $(x_1,y_1), (x_2,y_2), (x_3,y_3)$ is given by, 

Area of $\Delta=\frac{1}{2}[x_{1}(y_{2}-y_{3})+x_{2}(y_{3}-y_{1})+x_{3}(y_{1}-y_{2})]$

Therefore,

Area of \( \Delta \mathrm{ABC}=\frac{1}{2}[1(1-5)+2(5+1)+4(-1-1)] \)

\( =\frac{1}{2} [1 \times(-4)+2 \times 6+4 \times(-2)] \)

\( =\frac{1}{2}[-4+12-8] \)

\( =\frac{1}{2} \times 0 \)

\( =0 \)

Here,

Area of \( \Delta \mathrm{ABC}=0 \)

Therefore, points \( \mathrm{A}, \mathrm{B} \) and \( \mathrm{C} \) are collinear. 

Hence proved.

Updated on: 10-Oct-2022

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