Malati withdrew $\frac{2}{9}$ of the amount in her bank account on Wednesday, $\frac{2}{5}$ of the amount on Thursday and $\frac{1}{11}$ of the amount on Saturday. If she now has Rs. 35,500 left in her account, find the total amount in her account in the beginning?


Given:

Malati withdrew $\frac{2}{9}$ of the amount in her bank account on Wednesday, $\frac{2}{5}$ of the amount on Thursday and $\frac{1}{11}$ of the amount on Saturday.

She now has Rs. 35,500 left in her account.

To do:

We have to find the total amount in her account in the beginning.

Solution:

Let the total amount in her account, in the beginning, be $Rs.\ x$.

Malati withdrew $\frac{2}{9}$ of the amount in her bank account on Wednesday.

This implies,

According to the question,

$\frac{2}{9}x+\frac{2}{5}x+\frac{1}{11}x+35500=x$

$\frac{2(55)+2(99)+1(45)}{495}x+35500=x$

$x-\frac{110+198+45}{495}x=35500$

$x-\frac{353}{495}x=35500$

$\frac{495-353}{495}x=35500$

$\frac{142}{495}x=35500$

$x=\frac{35500\times495}{142}$

$x=Rs.\ 123750$

The total amount in her account in the beginning is Rs. 123750.

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Updated on: 10-Oct-2022

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