If p, q, and r are in continued proportion, find p if q=17 and r =289.
Given p, q, and r are in continued proportion; q = 17, and r = 289
To find p
Solution:
If p, q, and r in continued proportion
$\frac{p}{q} = \frac{q}{r}$
So $p = \frac{q^2}{r}$
$p = \frac{17^2}{289}$
$p = \frac{289}{289}$
$p = \frac{1}{1}$
So, $p = 1$ given p, q, and r in continued proportion where q = 17, and r = 289
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