If p, q, and r are in continued proportion, find p if q=17 and r =289.

Given p, q, and r are in continued proportion; q = 17, and r = 289
 

To find p

Solution:

If p, q, and r in continued proportion

$\frac{p}{q} = \frac{q}{r}$ 

So $p = \frac{q^2}{r}$ 

$p = \frac{17^2}{289}$ 

$p = \frac{289}{289}$ 

$p = \frac{1}{1}$ 

So, $p = 1$ given p, q, and r in continued proportion where q = 17, and r = 289