If $p=-2,\ q=-1$ and $r=3$, find the value of $3p^{2}q+5pq^{2}+2pqr$.
Given: $p=-2,\ q=-1$ and $r=3$.
To do: To find the value of $3p^{2}q+5pq^{2}+2pqr$.
Solution:
$3p^{2}q+5pq^{2}+2pqr$
$=3( -2)^2\times( -1)+5( -2)( -1)^2+2(-2)\times(-1)\times(3)$
$=-12-10-12$
$=-34$
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