If $p=-2,\ q=-1$ and $r=3$, find the value of $2 p^{2}-q^{2}+3 r^{2}$.
Given: $p=-2,\ q=-1$ and $r=3$.
To do: To find the value of $2p^{2}-q^{2}+3r^{2}$.
Solution:
As given, $p=-2,\ q=-1$ and $r=3$
$2p^{2}-q^{2}+3r^{2}$
$=2( -2)^2-( -1)^2+3(3)^2$
$=8-1+27$
$=34$
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