If $ A=\frac{5425}{1444}-\frac{2987}{3045}-\frac{493}{4284} $ and $ A $ lies between the integers $ m $ and $ m+1, $ then find the value of $ \frac{m}{10000} $
(write your answer in the decimal form)

Given: The value of A = $\frac{5425}{1444}-\frac{2987}{3045}-\frac{493}{4284} $ 

             A lies between integers m and m+1

To do: Find the value of $\frac{m}{1000}$

Solution

A = $\frac{5425}{1444} - \frac{2987}{3045} - \frac{493}{4284}$

    = 3.757 - 0.981 - 0.115 = 2.661

A lies between integers m and  $m + 1$

=> A = 2.661 lies between 2 and 2$+$1 or 2 and 3

So m = 2; and $\frac{m}{10000}$ = 0.0002  

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Updated on: 10-Oct-2022

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