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Solve the following linear equation.
$ m-\frac{m-1}{2}=1-\frac{m-2}{3} $.
Given:
$m-\frac{m-1}{2}=1-\frac{m-2}{3}$.
To do:
We have to solve the given linear equation.
Solution:
$m-\frac{m-1}{2}=1-\frac{m-2}{3}$
This implies,
$m-\frac{m-1}{2}+\frac{m-2}{3}=1$
$\frac{6(m) - 3( m-1) +2(m-2)}{6}=1$
$6m-3m+3+2m-4= 1\times6$
$5m-1= 6$
$5m=6+1$
$5m=7$
$m =\frac{7}{5}$
The value of $m$ is $\frac{7}{5}$.
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