Find the value of : $\frac{1}{1+a^{n-m}}+\frac{1}{1+a^{m-n}}$.


Given: $\frac{1}{1+a^{n-m}}+\frac{1}{1+a^{m-n}}$.

To do: To find the value of: $\frac{1}{1+a^{n-m}}+\frac{1}{1+a^{m-n}}$.

Solution:

$\frac{1}{1+a^{m-n}}+\frac{1}{1+a^{n-m}}$

$=\frac{1}{1+\frac{a^m}{a^n}}+\frac{1}{1+\frac{a^n}{a^m}}$

$=\frac{1}{\frac{a^m+a^n}{a^n}}+\frac{1}{\frac{a^m+a^n}{a^m}}$

$=\frac{a^n}{a^m+a^n}+\frac{a^m}{a^m+a^n}$

$=\frac{a^m+a^n}{a^m+a^n}$

$=1$

Thus, $\frac{1}{1+a^{n-m}}+\frac{1}{1+a^{m-n}}=1$.

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Updated on: 10-Oct-2022

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