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Find $A$ if $tan2A=cot( A-24^{o})$.
Given: $tan2A=cot( A-24^{o})$
To do: To find the value of A.
Solution:
$tan2A-cot( A-24^{o})$
$\Rightarrow tan 2A - tan[90^{o}-( A-24^{o})]$
$\Rightarrow tan 2A-tan( 90^{o}-A+24^{o})$
$\Rightarrow tan 2A = tan( 114^{o}- A)$
$\Rightarrow 2A =114^{o}-A$
$\Rightarrow 3A=114^{o}$
$\Rightarrow A=38^{o}$
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