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If the tangent at a point P to a circle with centre O cuts a line through O at Q such that $PQ = 24\ cm$ and $OQ = 25\ cm$. Find the radius of the circle.
Given:
The tangent at a point P to a circle with centre O cuts a line through O at Q such that $PQ = 24\ cm$ and $OQ = 25\ cm$.
To do:
We have to find the radius of the circle.
Solution:
$PQ = 24\ cm$ and $OQ = 25\ cm$
Let $XY$ be the tangent to the circle at $P$.
$OP\ perp\ XY$
In right angled triangle $OPQ$,
By Pythagoras theorem,
$OQ^2= OP^2+ PQ^2$
$(25)^2 = OP^2 + (24)^2$
$OP^2= 625 - 576$
$= 49$
$= 7^2$
Therefore,
$OP = 7\ cm$
The radius of the circle is 7 cm.
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