In a $\triangle ABC$, if $\angle A = 55^o, \angle B = 40^o$, find $\angle C$.


Given:

In a $\triangle ABC$,  $\angle A = 55^o, \angle B = 40^o$.

To do:

 We have to find $\angle C$.

Solution:

We know that,

Sum of the angles in a triangle is $180^o$.

Therefore,

$\angle A + \angle B + \angle C = 180^o$

$55^o+40^o+\angle C=180^o$

$\angle C=180^o-95^o$

$\angle C=85^o$

Hence, $\angle C=85^o$.

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Updated on: 10-Oct-2022

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