Fill in the blanks:
(i) $ \frac{-4}{13}-\frac{-3}{26}= $
(ii) $ \frac{-9}{14}+\ldots \ldots \ldots . . .=-1 $
(iii) $ \frac{-7}{9}+\ldots \ldots . . . .=3 $
(iv) ............ $ +\frac{15}{23}=4 $

To do :

We have to fill in the blanks.

Solution :

(i) Let the number in the blank be $x$.

This implies,

$\frac{-4}{13}-\frac{-3}{26}=x$

$x =\frac{-4}{13}+\frac{3}{26}$

$x = \frac{-4(2)+3(1)}{26}$

$x = \frac{(-8+3)}{26}$

$x = \frac{-5}{26}$

The required number is $\frac{-5}{26}$.

(ii) Let the number in the blank be $x$.

This implies,

$\frac{-9}{14}+x=-1$

$x =-1-\frac{-9}{14}$

$x=-1+\frac{9}{14}$

$x = \frac{-1(14)+9(1)}{14}$

$x=\frac{-14+9}{14}$

$x=\frac{-5}{14}$

The required number is $\frac{-5}{14}$.

(iii) Let the number in the blank be $x$.

This implies,

$\frac{-7}{9}+x=3$

$x =3-\frac{-7}{9}$

$x=3+\frac{7}{9}$

$x = \frac{3(9)+7(1)}{9}$

$x = \frac{(27+7)}{9}$

$x = \frac{34}{9}$

The required number is $\frac{34}{9}$.  

(iv) Let the number in the blank be $x$.

This implies,

$x+\frac{15}{23}=4$

$x =4-\frac{15}{23}$

$x = \frac{4(23)-15(1)}{23}$

$x = \frac{(92-15)}{23}$

$x = \frac{77}{23}$

The required number is $\frac{77}{23}$.   

Tutorialspoint

e

Updated on: 10-Oct-2022

20 Views

Kickstart Your Career

Get certified by completing the course

Get Started