Solve: $99\times 13=( 100-1)\times 13=\ldots \ldots \ldots \ldots \ldots \ldots$

Academic Mathematics NCERT Class 6

Given: $99\times 13=( 100-1)\times 13=\ldots \ldots \ldots \ldots$

To do: To solve: $99\times 13=( 100-1)\times 13=\ldots \ldots \ldots \ldots$

Solution:

$99\times 13$

$=( 100-1)\times 13$

$=1300-13=1287$ [$\because ( a-b)x=ax-bx$ from distributive law]

Thus, $99\times13=( 100-1)\times13=1287$.

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Updated on: 10-Oct-2022

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