Divide the following.

$ x^{2} y-3 x y \ by \ y $

Given: $ x^{2} y-3 x y \ by \ y $

To do:  Find the solution is $ x^{2} y-3 x y$ is divided  by $y $

Solution: $x^2 y  -  3 x y$  divided by $y$

Take y as common from  $x^2 y  -  3 x y$  

$y (x^2    -  3 x  )$ 

now divide it by $y$

$y \frac{x^2    -  3 x }{y}$

$y \ and \ y$ get cancel , 

 Therefore, $x^2   -  3 x $  is the answer