Construct a rectangle $ABCD$, where $AB =12\ cm,\ BC=5\ cm$.
Given: A rectangle $ABCD$, where $AB =12\ cm,\ BC=5\ cm$.
To do: To construct $ABCD$.
Solution:
Follow the steps of construction:-
1. Draw $AB=12\ cm$.
2. At point $B$, draw an angle $ABX=90^o$.
3. Take point $B$ as center and draw an arc with radius $5\ cm$, which intersects $BX$ at point $C$.
4. At point $C$, draw an angle $YCB=90^o$.
5. Take point $C$ as center, draw an arc with radius $12\ cm$ which intersects $YC$ at point $D$.
6. Join $D$ to $C$.
Thus, $ABCD$ is the required rectangle.
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