Construct a $∆ABC$ in which $BC = 3.6\ cm, AB + AC = 4.8\ cm$ and $\angle B = 60^o$.
Given:
A $∆ABC$ in which $BC = 3.6\ cm, AB + AC = 4.8\ cm$ and $\angle B = 60^o$.
To do:
We have to construct the given triangle.
Solution:
Steps of construction:
(i) Draw a line segment $BC = 3.6\ cm$.
(ii) At $B$, draw a ray $BX$ making an angle of $60^o$ and cut off $BE = 4.8\ cm$.
(iii) Join $EC$.
(iv) Draw perpendicular bisector of $CE$ which intersects $BE$ at $A$.
(v) Join $AC$.
Therefore,
$\triangle ABC$ is the required triangle.
Related Articles
- Construct a $∆ABC$ in which $AB + AC = 5.6\ cm, BC = 4.5\ cm$ and $\angle B = 45^o$.
- Using ruler and compasses only, construct a $∆ABC$, given base $BC = 7\ cm, \angle ABC = 60^o$ and $AB + AC = 12\ cm$.
- Construct $\vartriangle ABC$ in which $BC=7\ cm,\ \angle B=75^{o}$ and $AB+AC=12\ cm$.
- Construct a $\triangle ABC$ in which $BC = 3.4\ cm, AB - AC = 1.5\ cm$ and $\angle B = 45^o$.
- Construct $∆ABC$ such that $AB=2.5\ cm$, $BC=6\ cm$ and $AC=6.5\ cm$. Measure $\angle B$.
- Construct $∆ABC$ with $BC = 7.5\ cm$, $AC = 5\ cm$ and $\angle C = 60^{\circ}$.
- Tick the correct answer and justify : In $∆ABC, AB = 6\sqrt3\ cm, AC = 12\ cm$ and $BC = 6\ cm$. The angle B is:(a) $120^o$(b) $60^o$(c) $90^o$(d) $45^o$
- Construct a $\vartriangle ABC$ in which $AB\ =\ 6\ cm$, $\angle A\ =\ 30^{o}$ and $\angle B\ =\ 60^{o}$, Construct another $\vartriangle AB’C’$ similar to $\vartriangle ABC$ with base $ AB’\ =\ 8\ cm$.
- Construct $∆ABC$, given $m\angle A = 60^{\circ}$, $m\angle B = 30^{\circ}$ and $AB = 5.8\ cm$.
- ∆ABC ~ ∆LMN. In ∆ABC, AB = 5.5 cm, BC = 6 cm, CA = 4.5 cm. Construct ∆ABC and ∆LMN such that $\frac{BC}{MN} \ =\ \frac{5}{4}$.
- Using ruler and compasses only, construct a $\triangle ABC$, from the following data:$AB + BC + CA = 12\ cm, \angle B = 45^o$ and $\angle C = 60^o$.
- Construct a triangle \( \mathrm{ABC} \) in which \( \mathrm{BC}=7 \mathrm{~cm}, \angle \mathrm{B}=75^{\circ} \) and \( \mathrm{AB}+\mathrm{AC}=13 \mathrm{~cm} \).
- Construct a triangle \( \mathrm{ABC} \) in which \( \mathrm{BC}=8 \mathrm{~cm}, \angle \mathrm{B}=45^{\circ} \) and \( \mathrm{AB}-\mathrm{AC}=3.5 \mathrm{~cm} \).
- In a right triangle ABC, angle B is 90 degrees and AB = 12cm and BC = 5 cm. Find the value of AC.(a) 12 cm(b) 15 cm(c) 13 cm(d)14 cm
Kickstart Your Career
Get certified by completing the course
Get Started
Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies