In a Parallelogram $ABCD, AB = 18\ cm, BC=12\ cm, AL \perp\ DC, AM \perp\ BC$ and $AL = 6.4\ cm$. Find the length of $AM$.

Given:

In a Parallelogram $ABCD, AB = 18\ cm, BC=12\ cm, AL \perp\ DC, AM \perp\ BC$ and $AL = 6.4\ cm$.
To do:

We have to find the length of $AM$.
Solution:

We know that,

Area of a parallelogram $=$ Base $\times$ Height

Therefore,

$AL\times DC=AM\times BC$

$6.4\times 18=AM\times 12$   ($AB=DC=18\ cm$, opposite sides of a parallelogram are equal)

$AM=\frac{6.4\times18}{12}$

$AM=3.2\times3$

$AM=9.6\ cm$

The length of AM is 9.6 cm.

Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

364 Views

Kickstart Your Career

Get certified by completing the course

Get Started