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Construct $∆ABC$ such that $AB=2.5\ cm$, $BC=6\ cm$ and $AC=6.5\ cm$. Measure $\angle B$.
To do: To construct $∆ABC$ such that $AB=2.5\ cm$, $BC=6\ cm$ and $AC=6.5\ cm$ and measure $\angle B$.
Steps of construction -
- Let us draw a line segment $BC=6\ cm$.
- Assuming $B$ as the center, let us draw an arc of radius $2.5\ cm$.
- Assuming point $C$ as the center let us draw an arc of radius $6.5\ cm$.
- Both the arcs intersect each other at the point $A$.
- Now let us join $AB$ and $AC$.
Thus, $ABC$ is the required triangle that has been constructed.
On measuring $\angle B$ with the help of a protractor we find that it is a right-angled triangle ABC, where $\angle B = 90^{\circ}$.
Updated on: 10-Oct-2022
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