Construct $∆ABC$ with $BC = 7.5\ cm$, $AC = 5\ cm$ and $\angle C = 60^{\circ}$.
To do: To construct $∆ABC$ with $BC = 7.5\ cm$, $AC = 5\ cm$ and $m \angle C = 60^{\circ}$.
Steps of construction :
- Let us draw a line segment $BC$ with the length of $7.5\ cm$.
- From the point $C$, let us draw a ray $CX$ making an angle of $60^{\circ}$ with $BC$ such that $\angle ACB=60^{\circ}$.
- Assuming $C$ as the center, let us draw an arc of radius $5\ cm$ that cuts $CX$ at the point $A$.
- Now let us join $AB$ to get the required triangle.
$\triangle ABC$ is the required triangle.
Hence constructed!
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