An ant travels a distance of $8\ cm$ from $P$ to $Q$ and then moves a distance of $6\ cm$ at right angles to $PQ$. Find its resultant displacement.
As given, An ant is moved from $P$ to $Q$ with a distance of $8\ cm$ and then from $Q$ to $R$ a distance of $6\ cm$ at the right angle. Let the ant reaches the point $R$.
Distance traveled by the ant at the path $PQ=8\ cm$
And $QR=6\ cm$
$PR$ is the displacement.
In right-angled $\vartriangle PQR$, using Pythagoras theorem
$PR^2=PQ^2+QR^2$
$=8^2+6^2$
$=64+36$
$=100$
Or $PR=\sqrt{100}$
Or $PR=10\ cm$
Therefore, the resultant displacement is $10\ cm$.
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