$PQR$ is a triangle, right-angled at $P$. If $PQ=10\ cm$ and $PR=24\ cm$, find $QR$.

AcademicMathematicsNCERTClass 7

Given:

$PQR$ is a triangle, right-angled at P. 

$PQ  = 10\ cm $   ;    $PR = 24\ cm$

To Find:  The value of $QR$.

Solution:

Since its aright angle triangle apply Pythagoras formula,

angle P = 90°   ;  QR is hypotenuse.

$QR^ 2    =  PQ^ 2    +   PR^2$

$QR^ 2    =  10^2    +   24^2$

$QR^ 2    =  100 + 576$

$QR^ 2    =   676$

$QR    =  \sqrt{676}$

$QR   =  \sqrt{26\times 26}$

$QR    =  26$ cm.

Therefore the value of QR is 26 cm.

raja
Updated on 10-Oct-2022 13:34:29

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