$PQR$ is a triangle, right-angled at $P$. If $PQ=10\ cm$ and $PR=24\ cm$, find $QR$.
Given:
$PQR$ is a triangle, right-angled at P.
$PQ = 10\ cm $ ; $PR = 24\ cm$
To Find: The value of $QR$.
Solution:
Since its aright angle triangle apply Pythagoras formula,
angle P = 90° ; QR is hypotenuse.
$QR^ 2 = PQ^ 2 + PR^2$
$QR^ 2 = 10^2 + 24^2$
$QR^ 2 = 100 + 576$
$QR^ 2 = 676$
$QR = \sqrt{676}$
$QR = \sqrt{26\times 26}$
$QR = 26$ cm.
Therefore the value of QR is 26 cm.
Related Articles
- PQR is a triangle, right-angled at P. If PQ=10cm and PR=24 , find QR
- In $\triangle P Q R$, if $PQ=10\ cm$, $QR=8\ cm$ and $PR=6\ cm$ then find $\angle R=?$
- In $ΔPQR$, right-angled at $Q, PR + QR = 25\ cm$ and $PQ = 5\ cm$. Determine the values of $sin\ P, cos\ P$ and $tan\ P$.
- Draw $∆PQR$ with $PQ=4\ cm$, $QR=3.5\ cm$ and $PR=4\ cm$. What type of triangle is this?
- In triangle PQR, right angled at Q, PR$+$QR=25cm and PQ=5cm.Determine the values of sinP, cosP, tanP.
- Construct the right angled $∆PQR$, where $m\angle Q = 90^{\circ},\ QR = 8cm$ and $PR = 10\ cm$.
- In $\triangle PQR$, right angled at $Q, PQ = 4\ cm$ and $RQ = 3\ cm$. Find the values of $sin\ P, sin\ R, sec\ P$ and $sec\ R$.
- In figure below, \( \mathrm{PQR} \) is a right triangle right angled at \( \mathrm{Q} \) and \( \mathrm{QS} \perp \mathrm{PR} \). If \( P Q=6 \mathrm{~cm} \) and \( P S=4 \mathrm{~cm} \), find \( Q S, R S \) and \( Q R \)."
- $ABC$ is a triangle, right-angled at $C$. If $AB=25\ cm$ and $AC=7\ cm$, find $BC$.
- \( \triangle \mathrm{ABC} \sim \triangle \mathrm{PQR} . \quad \) If \( \quad \mathrm{AB}+\mathrm{BC}=12 \mathrm{~cm} \) \( \mathrm{PQ}+\mathrm{QR}=15 \mathrm{~cm} \) and \( \mathrm{AC}=8 \mathrm{~cm} \), find \( \mathrm{PR} \).
- $E$ and $F$ are points on the sides $PQ$ and $PR$ respectively of a $\triangle PQR$. For each of the following cases, state whether $EF \| QR$:$PQ = 1.28\ cm, PR = 2.56\ cm, PE = 0.18\ cm$ and $PF = 0.36\ cm$
- M and N are points on the sides PQ and PR respectively of a $\triangle PQR$. For each of the following cases, state whether $MN \parallel QR$:$PQ = 1.28\ cm, PR = 2.56\ cm, PM = 0.16\ cm, PN = 0.32\ cm$
- \( \triangle \mathrm{PQR} \sim \triangle \mathrm{ZYX} . \quad \) If \( \mathrm{PQ}: \mathrm{ZY}=5: 3 \) and \( \mathrm{PR}=10 \mathrm{~cm} \), find \( \mathrm{ZX} \).
- Construct a triangle \( \mathrm{PQR} \) in which \( \mathrm{QR}=6 \mathrm{~cm}, \angle \mathrm{Q}=60^{\circ} \) and \( \mathrm{PR}-\mathrm{PQ}=2 \mathrm{~cm} \).
- $A B C$ is a triangle, right-angled at $C$. If $A B=25$ cm and $AC=7$ cm, find $BC$.
Kickstart Your Career
Get certified by completing the course
Get Started