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# A train starting from a railway station and moving with uniform acceleration attains a speed $40\ km/h$ in $10\ minutes$. Find its acceleration.

Here, initial velocity $u=0$

Final velocity of the train $v=40\ km/h=40\times\frac{5}{18}=\frac{100}{9}\ ms^{-1}$

Time $t=10\ minute=10\times 60\ second=600\ second$

Therefore, acceleration, $a=\frac{v-u}{t}$

$=\frac{\frac{100}{9}-0}{600}$

$=\frac{100}{600\times9}$

$=0.019\ m/s^2$

therefore, acceleration of the train is $0.019\ m/s^2$.

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