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A train starting from a railway station and moving with uniform acceleration attains a speed $40\ km/h$ in $10\ minutes$. Find its acceleration.
Here, initial velocity $u=0$
Final velocity of the train $v=40\ km/h=40\times\frac{5}{18}=\frac{100}{9}\ ms^{-1}$
Time $t=10\ minute=10\times 60\ second=600\ second$
Therefore, acceleration, $a=\frac{v-u}{t}$
$=\frac{\frac{100}{9}-0}{600}$
$=\frac{100}{600\times9}$
$=0.019\ m/s^2$
therefore, acceleration of the train is $0.019\ m/s^2$.
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