A train accelerates from $36\ km/h$ to $54\ km/h$ in $10\ sec$. Calculate the acceleration.

Here initial velocity $u=36\ km/h=36\times\frac{5}{18}\ m/s=10\ m/s$

Final velocity $v=54\ km/h=54\times\frac{5}{18}\ m/s=15\ m/s$

Time $t=10\ sec.$

Therefore, acceleration $a=\frac{v-u}{t}$

$=\frac{15-10}{10}$

$=\frac{5}{10}$

$=0.5\ m/s^2$

Therefore, acceleration is $0.5\ m/s^2$.

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Updated on: 10-Oct-2022

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