A train starting from rest moves with a uniform acceleration of $0.2\ m/s^2$ for $5\ minutes$. Calculate the speed acquired.

Academic Physics NCERT Class 9

Here initial velocity $u=0$

Acceleration $a=0.2\ m/s^2$

Time $t=5\ minutes=5\times60=300\ sec.$

Let $v$ be the final velocity.

On using the equation of motion: $v=u+at$

Or $v=0+0.2\times300$

Or $v=60\ m/s$

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Updated on: 10-Oct-2022

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