A train starting from stationary position and moving with uniform acceleration attains a speed of 36 km per hour in 10 minutes. Find its acceleration.


Initial velocity of the train $u=o$

Final velocity $v=36\ km/h=36\times\frac{5}{18}=10\ m/s$

Time $t=10\ minutes=10\times60\ sec.= 600sec.

Acceleration $a=\frac{v-u}{t}$

Or $a=\frac{10-0}{600}$

Or $a=\frac{1}{60}\ m/s^2$

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Updated on: 10-Oct-2022

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