A ship is moving at a speed of $56\ km/h$. One second later, it is moving at $58 km/h$. What is its acceleration?

Here given, the initial velocity $u=56\ km/h=56\times\frac{5}{18}=\frac{280}{18}\ m/s$

Final velocity of the ship $v=58\ km/h=58\times\frac{5}{18}\ m/s=\frac{290}{18}\ m/s$

Time $t=1\ second$

Therefore, acceleration $a=\frac{v-u}{t}$

$=\frac{\frac{290}{18}\ m/s-\frac{280}{18}\ m/s}{1\ second}$

$=\frac{10}{18}\ m/s^2$

$=0.55\ m/s^2$

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Updated on: 10-Oct-2022

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