A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area $1080m^2$? (If required you can split the tiles in whatever way you want to fill up the corners).

Given:

A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. 

The area of the floor$=1080\ m^2$

To do:

We have to find the number of tiles required to cover the floor of area $1080m^2$.

Solution:

Area of a tile $=24\ cm \times 10\ cm=240\ cm^2$

Area of the floor$=1080\ m^2=1080\times(100\ cm)^2$

                              $=1080\times10000\ cm^2=10800000\ cm^2$

Number of tiles required$=\frac{Area\ of\ the\ floor}{Area\ of\ a\ tile}$

                                            $=\frac{10800000}{240}$

                                            $=45000$

Therefore, $45000$ tiles are required to cover the floor.

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Updated on: 10-Oct-2022

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