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A flag pole $18\ m$ high casts a shadow $9.6\ m$ long. Find the distance of the top of the pole from the far end of the shadow.
Given: A flag pole $18\ m$ high casts a shadow $9.6\ m$ long.
To do: To find the distance of the top of the pole from the far end of the shadow.
Solution:
As given , height of the flag, $AB=18\ m$, Shadow length $BC=9.6\ m$
Distance between top of flag and end of shadow is $AC$.
In $\vartriangle ABC$ Using pythagoras theorem,
$AC^2=18^2+9.6^2$
$\Rightarrow AC^2=324+92.16$
$\Rightarrow AC^2=416.16$
$\Rightarrow AC^2=( 20.4)^2$
$\Rightarrow AC=20.4\ m$
Thus, the distance of the top of the pole from the far end of the shadow is $20.4\ m$.
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