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If a pole $6\ m$ high casts a shadow $2\sqrt{3}\ m$ long on the ground, then find the sun’s elevation.
Given: A pole $6\ m$ high casts a shadow $2\sqrt{3}\ m$ long on the ground.
To do: To find the sun’s elevation.
Solution:
Let height $=6\ m$
length of shadow $=2\sqrt{3}\ m$
$\theta$ is angle of elevation
$tan\theta=\frac{height}{shadow-length}$
$=\frac{6}{2\sqrt{3}}$
$=\sqrt{3}$
$=tan60^o$
$\therefore \theta=60^o$
Thus, angle of elevation is $60^o$
Updated on: 10-Oct-2022
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