If a pole $6\ m$ high casts a shadow $2\sqrt{3}\ m$ long on the ground, then find the sun’s elevation.

Given: A pole $6\ m$ high casts a shadow $2\sqrt{3}\ m$ long on the ground.

To do: To find the sun’s elevation.

Solution:
Let height $=6\ m$

length of shadow $=2\sqrt{3}\ m$

$\theta$ is angle of elevation

$tan\theta=\frac{height}{shadow-length}$

$=\frac{6}{2\sqrt{3}}$

$=\sqrt{3}$

$=tan60^o$

$\therefore \theta=60^o$

Thus, angle of elevation is $60^o$

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Updated on: 10-Oct-2022

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