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A Sm 60 cm high vertical pole casts a shadow 3m 20cm. Find at the same time
the length of the shadow cast by another pole10m 50cm high
Given:
Height of pole = 5 m 60 cm = 560 cm (1 m = 100 cm ; 5 m = 500 cm)
Length of shadow = 3 m 20 cm = 320 cm
To do: Find the shadow length casted by another pole of height 10m 50cm high
Solution:
Ratio = Height of pole : Length of shadow
= 560 : 320
Ratio = 7 : 4
Height of pole = 10 m 50 cm = 1050 cm
Length of shadow = $x$
Ratio will be same, because the time is same.
$1050 : x$ = 7 : 4 $\frac{1050}{ x} = \frac{7}{4}$
$\frac{1}{ x} = \frac{7 }{ 4 \times 1050}$
$\frac{1}{ x} = \frac{1}{4 \times 150}$
$\frac{1}{ x} = \frac{1}{ 600}$
$x$ = 600 cm
$x$ = 6 m
The Length of shadow of height 10 m 50 cm is 6 m
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