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A bag contains tickets numbered $ 11,12,13, \ldots, 30 $. A ticket is taken out from the bag at random. Find the probability that the number on the drawn ticket is a multiple of 7.
Given:
A bag contains tickets numbered \( 11,12,13, \ldots, 30 \). A ticket is taken out from the bag at random.
To do:
We have to find the probability that the number on the drawn ticket is a multiple of 7.
Solution:
A bag contains tickets numbered \( 11,12,13, \ldots, 30 \).
This implies,
The total number of possible outcomes $n=20$.
Multiples of 7 from 11 to 30 are $14, 21$ and $28$.
Total number of favourable outcomes $=3$.
We know that,
Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$
Therefore,
Probability that the number on the drawn ticket is a multiple of 7 $=\frac{3}{20}$
The probability that the number on the drawn ticket is a multiple of 7 is $\frac{3}{20}$.
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