A bag contains cards which are numbered from 2 to 90. A card is drawn at random from the bag. Find the probability that it bears a two digit number.
Given:
A bag contains cards which are numbered from 2 to 90. A card is drawn at random from the bag.
To do:
We have to find the probability that it bears a two digit number.
Solution:
A bag contains cards numbered \( 2,3,4, .., 89,90 \).
This implies,
The total number of possible outcomes $n=89$.
Two digit numbers from 2 to 90 are $10, 11, .........., 89, 90$.
Total number of favourable outcomes $=81$.
We know that,
Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$
Therefore,
Probability that the card bears a two digit number $=\frac{81}{89}$
The probability that it bears a two digit number is $\frac{81}{89}$.
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