Suppose we have a matrix consisting of 0s and 1s, we can choose any number of columns in the matrix and flip every cell in that column. converting a cell changes the value of that cell from 0 to 1 or from 1 to 0. we have to find the maximum number of rows that have all values equal after some number of flips. So if the matrix is like −
The output will be 2. This is because after converting values in the first two columns, the last two rows have equal values.
To solve this, we will follow these steps −
Let us see the following implementation to get better understanding −
class Solution(object): def maxEqualRowsAfterFlips(self, matrix): x = matrix m = len(matrix) n = len(matrix ) r =0 for i in x: c=0 a=[l ^ 1 for l in i] for j in x: if j== i or j ==a: c+=1 r=max(c, r) return r ob = Solution() print(ob.maxEqualRowsAfterFlips([[0,0,0],[0,0,1],[1,1,0]]))