# 123 Number Flip in Python

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Suppose we have an integer n, where only 1, 2, and 3 these digits are present. We can flip one digit to a 3. Then find the maximum number we can make.

So, if the input is like 11332, then the output will be 31332

To solve this, we will follow these steps −

• li := a list by digits of n

• for x in range 0 to size of li - 1, do

• if li[x] is not '3', then

• li[x] := '3'

• return the number by merging digits from li

• return n

Let us see the following implementation to get better understanding −

## Example

Live Demo

class Solution:
def solve(self, n):
li = list(str(n))
for x in range(len(li)):
if li[x] != '3':
li[x] = '3'
return int(''.join(li))
return n
ob = Solution()
print(ob.solve(11332))

## Input

11332

## Output

31332