Find the perimeter of each of the following shapes :(a) A triangle of sides $3 \mathrm{~cm}, 4 \mathrm{~cm}$ and $5 \mathrm{~cm}$.(b) An equilateral triangle of side $9 \mathrm{~cm}$.(c) An isosceles triangle with equal sides $8 \mathrm{~cm}$ each and third side $6 \mathrm{~cm}$.

AcademicMathematicsNCERTClass 6

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To do:

We have to find the perimeter of each of the given shapes.

Solutions:

We know that,

Perimeter is defined as the length of the outline of a shape.

To find the perimeter of a shape, just add the lengths of all the sides of the shape.

Therefore,

(a) The perimeter of the triangle whose sides are $3\ cm, 4\ cm$ and $5\ cm= 3\ cm+4\ cm+5\ cm$

$=12\ cm$

(b) The perimeter of the equilateral triangle of side $9\ cm=3\times$ Length of the side.

$= 3\times9$

$=27\ cm$

(c) The perimeter of an isosceles triangle with equal sides $8\ cm$ and third side $6\ cm =8\ cm+8\ cm+6\ cm$

$=22\ cm$.

Updated on 10-Oct-2022 13:36:27

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