Construct a triangle with sides $ 5 \mathrm{~cm}, 5.5 \mathrm{~cm} $ and $ 6.5 \mathrm{~cm} $. Now, construct another triangle whose sides are $ 3 / 5 $ times the corresponding sides of the given triangle.
Given:
A triangle of sides \( 5 \mathrm{~cm}, 5.5 \mathrm{~cm} \) and \( 6.5 \mathrm{~cm} \).
To do:
We have to Construct a triangle with sides \( 5 \mathrm{~cm}, 5.5 \mathrm{~cm} \) and \( 6.5 \mathrm{~cm} \). Now, construct another triangle whose sides are \( 3 / 5 \) times the corresponding sides of the given triangle.
Solution:
Steps of construction:
(i) Draw a line segment $BC = 5.5\ cm$.
(ii) With centre $B$ and radius $5\ cm$ and with centre $C$ and radius $6.5\ cm$, draw arcs that intersect each other at $A$.
(iii) Join $BA$ and $CA$.
$ABC$ is the required triangle.
(iv) At $B$, draw a ray $BX$ making an acute angle and cut off five equal parts from $BX$.
(v) Join $CB_5 and draw $B_3D\ \parallel\ B_5C$ which meets $BC$ at $D$.
From $D$, draw $DE\ \parallel\ CA$ which meets $AB$ at $E$.
$EBD$ is the required triangle.
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