Corporate Flight Bookings in Python

Suppose we have n flights, and they are labeled from 1 to n. We have a list of flight bookings. The i-th booking indicates using bookings[i] = [i, j, k] this means that we booked k seats from flights labeled i to j inclusive. Find an array answer of length n, showing the number of seats booked on each flight in order of their label. So if the input is like [[1,2,10],[2,3,20],[2,5,25]] and n = 5, then the output will be [10, 55, 45, 25, 25].

To solve this, we will follow these steps −

• res := make one array of size n, and fill this with 0
• for each entry i in bookings
  • res[i[0] - 1] := res[i[0] - 1] + i[2]
  • if i[1] < n, then res[i[1]] := res[i[1]] – i[2]
• for i in range 1 to n – 1
  • res[i] := res[i] + res[i - 1]
• return res

Let us see the following implementation to get better understanding −

Example

 Live Demo

class Solution(object):
   def corpFlightBookings(self, bookings, n):
      res = [0 for i in range(n)]
      for i in bookings:
         res[i[0]-1]+=i[2]
         if(i[1]<n):
            res[i[1]]-=i[2]
      for i in range(1,n):
         res[i]+=res[i-1]
      return res
ob = Solution()
print(ob.corpFlightBookings([[1,2,10],[2,3,20],[2,5,25]],5))

Input

[[1,2,10],[2,3,20],[2,5,25]]
5

Output

[10, 55, 45, 25, 25]

Arnab Chakraborty

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Updated on: 30-Apr-2020

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