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Count numbers < = N whose difference with the count of primes upto them is > = K in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 226 Views

Given two integers N and K, the goal is to find the count of numbers such that they follow below conditions −Number=K Where count is the number of prime numbers less than or equal to Number.For ExampleInputN = 5, K = 2OutputCount of numbers < = N whose difference with the count of primes upto them is > = K are: 2ExplanationThe numbers that follow the conditions are: 5 ( 5−2>=2 ) and 4 ( 4−2>=2 )InputN = 10, K = 6OutputCount of numbers < = N whose difference with the count of primes upto them is > = K ...

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Count the number of pop operations on stack to get each element of the array in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 789 Views

Given an array of numbers and a stack. All the elements of the array are present inside the stack The goal is to find the count of pop operations required for getting individual array elements.The stack is filled in decreasing order, the first element is highest and top element is lowest.For ExampleInputStack [ 7, 6, 2, 1 ] array : 2, 1, 6, 7OutputCount of number of pop operations on stack to get each element of the array are: 3 1 0 0ExplanationTraversing array from 0th index, To get 2 we will pop stack three times. So arr[0] is 3. ...

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Count of all possible values of X such that A % X = B in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 292 Views

Given two integers A and B and a number X. The goal is to find the count of values that X can have so that A%X=B. For the above equation if, A==B then infinite values of X are possible, so return −1. If A < B then there would be no solution so return 0. If A>B then return count of divisors of (AB) as result.For ExampleInputA=5, B=2OutputCount of all possible values of X such that A % X = B are: 1Explanation5%3=2. So X is 3 here.InputA=10, B=10OutputCount of all possible values of X such that A % X ...

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Count of arrays in which all adjacent elements are such that one of them divide the another in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 481 Views

Given two integers named ‘one’ and ‘another’. The goal is to find the number of possible arrays such that −The elements in the array are in range between 1 and ‘another’.All elements of array are such that arr[i] divides arr[i+1] or arr[i+1] divides arr[i+2]....and so on.The length of the array is ‘one’.For ExampleInputone = 3, another = 2OutputCount of arrays in which all adjacent elements are such that one of them divide the another are: 8ExplanationThe arrays will be: [ 1, 1, 1 ], [ 1, 1, 2 ], [ 1, 2, 1 ], [ 1, 2, 2 ], [ ...

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Count the number of intervals in which a given value lies in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 507 Views

Given a 2D array arr[][] containing intervals and a number ‘value’. The goal is to find the number of intervals present in arr between which value lies. For example intervals are [ [1, 5], [3, 7] ] and value=4 then it lies in both these intervals and count would be 2.For ExampleInputarr[4][2] = { { 1, 20 }, { 12, 25 }, { 32, 40 }, { 15, 18 } } value=16OutputCount of number of intervals in which a given value lies are: 3ExplanationThe value 16 lies between 1−20, 12−25 and 15−18Inputarr[4][2] = {{ 1, 20 }, { 20, 30 ...

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Count the number of non-increasing subarrays in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 471 Views

Given an array arr[] containing positive integers. The goal is to find the number of subarrays of length at least 1 which are non−increasing. If arr[]= {1, 3, 2}, then subarrays will be {1}, {2}, {3}, {3, 2}. Count is 4.For ExampleInputarr[] = {5, 4, 5}OutputCount of number of non-increasing subarrays are: 7ExplanationThe subarrays will be − {5}, {4}, {5}, {5, 4}Inputarr[] = {10, 9, 8, 7}OutputCount of number of non−increasing subarrays are − 10ExplanationThe subarrays will be − {10}, {9}, {8}, {7}, {10, 9}, {9, 8}, {8, 7}, {10, 9, 8}, {9, 8, 7}, {10, 9, 8, 7}Approach used ...

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Count number of subsets having a particular XOR value in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 505 Views

Given an array arr[ ] containing positive integers and a value match. The goal is to find the subsets of arr[] that contain elements that have XOR = match.For ExampleInputarr[] = {4, 2, 8, 10} match=12OutputCount of number of subsets having a particular XOR value are: 2ExplanationSubsets of arr with XOR of elements as 0 are − [ 4, 8 ], [4, 2, 10]Inputarr[] = {3, 5, 2, 7} match=5OutputCount of number of subsets having a particular XOR value are− 2Explanationubsets of arr with XOR of elements as 0 are− [ 5 ], [2, 7]Approach used in the below program ...

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Count number of strings (made of R, G and B) using given combination in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 444 Views

Given three numbers R, G and B and letters ‘R’, ‘G’ and ‘B’ only. The goal is to find the count of possible strings that can be made using at least R Rs, at least G Gs and at least B Bs in it. The numbers R, G and B have sum less than or equal to the length of strings possible.For ExampleInputR = 1, G = 1, B = 1 length=3OutputCount of number of strings (made of R, G and B) using given combination are − 6ExplanationThe possible strings will be : “RGB”, “RBG”, “BRG”, “BGR”, “GRB”, “GBR”. That ...

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Count the number of currency notes needed in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 783 Views

Given an amount in rupees that one has to pay, say pay_rupees and an unlimited amount of banknotes that have value as Rupees_amount_1 and Rupees_amount_2. The goal is to pay pay_rupees using exactly the total number of notes=distribution_total and count the number of type Rupees_amount_1 notes required. If there is no solution to pay then return −1 as answer.For ExampleInputRupees_amount_1 = 1, Rupees_amount_2 = 5, pay_Rupees = 11 distribution_total = 7OutputCount of number of currency notes needed are − 6Explanation6*1 + 5*1 = 11 and notes=6+1=7InputRupees_amount_1 = 2, Rupees_amount_2 = 3, pay_Rupees = 10 distribution_total = 4OutputCount of number of ...

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Construct sum-array with sum of elements in given range in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 659 Views

Given an array arr[ ] containing integers only and an odd number sum. The goal is to create a sum array arr_2[ ] such each arr_2[i] is the sum of previous sum/2 elements of arr[] + arr[i] + next sum/2 elements of arr[]. If sum is 1 then arr_2[i]=arr[i]For ExampleInputarr[] = { 4, 1, 7, 5, 2, 9} sum=3OutputConstruction of sum-array with sum of elements in given range are: 5 12 13 14 16 17 17 9 3ExplanationThe sum array is constructed as: arr_2[0]=arr[0]+arr[1] = 4+1 = 5 arr_2[1]=arr[0]+arr[1]+arr[2] = 4+1+7 = 12 arr_2[2]=arr[1]+arr[2]+arr[3] = 1+7+5 = 13 arr_2[3]=arr[2]+arr[3]+arr[4] = ...

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