Filter tuples according to list element presence in Python

PythonServer Side ProgrammingProgramming

When it is required to filter tuples based on the list element that is present, list comprehension can be used.

A list can be used to store heterogeneous values (i.e data of any data type like integer, floating point, strings, and so on).

A list of tuple basically contains tuples enclosed in a list. The list comprehension is a shorthand to iterate through the list and perform operations on it.

Below is a demonstration of the same −

Example

Live Demo

my_list = [(11, 14), (54, 56, 87), (98, 0, 10), (13, 76)]
target_list = [34, 11]

print("The list is : ")
print(my_list)

my_result = [tup for tup in my_list if any(i in tup for i in target_list)]

print("The filtered tuple from the list is: ")
print(my_result)

Output

The list is :
[(11, 14), (54, 56, 87), (98, 0, 10), (13, 76)]
The filtered tuple from the list is:
[(11, 14)]

Explanation

  • A list of tuple is defined, and is displayed on the console.
  • Another target list is defined.
  • Based on this target list, the original list of tuple is filtered out, using list comprehension.
  • It is then converted to a list of tuple.
  • This is assigned to a value.
  • It is displayed on the console.
raja
Published on 12-Mar-2021 05:43:25
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