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# Conversion to N*N tuple matrix in Python

When it is required to convert an N*N tuple into a matrix, a simple loop and the * operator can be used.

The * operator can be used to get the product of two values. It can also be used to multiple a single value multiple times and display it on the console.

Below is a demonstration of the same −

## Example

my_tuple_1 = ((11, 14), (0, 78), (33, 11), (10, 78)) print("The tuple of tuple is : ") print(my_tuple_1) N = 4 print("The value of N has been initialized to "+ str(N)) my_result = [] for tup in my_tuple_1 : my_result.append( tup +(0, ) * (N - len(tup))) print("The tuple after filling in the values is: ") print(my_result)

## Output

The tuple of tuple is : ((11, 14), (0, 78), (33, 11), (10, 78)) The value of N has been initialized to 4 The tuple after filling in the values is: [(11, 14, 0, 0), (0, 78, 0, 0), (33, 11, 0, 0), (10, 78, 0, 0)]

## Explanation

- A nested tuple is defined and is displayed on the console.
- The value of 'N' is defined, and displayed.
- Another empty list is created.
- The nested tuple is iterated, and 0 is added after every value, and repeated 'N- len(tuple)' times.
- This is assigned to a value.
- It is displayed on the console.

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