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The clear() method of the class java.util.ArrayList removes all of the elements from this list. The list will be empty after this call returns.Exampleimport java.util.ArrayList; public class ArrayListDemo { public static void main(String[] args) { ArrayList arrlist = new ArrayList(5); arrlist.add(20); arrlist.add(30); arrlist.add(10); arrlist.add(50); for (Integer number : arrlist) { System.out.println("Number = " + number); } int retval = arrlist.size(); System.out.println("List consists of "+ retval +" elements"); ... Read More
The remove(Object) method of the class java.util.ArrayList removes the first occurrence of the specified element from this list, if it is present. If the list does not contain the element, it is unchanged.Exampleimport java.util.ArrayList; public class ArrayListDemo { public static void main(String[] args) { ArrayList arrlist = new ArrayList(5); arrlist.add("G"); arrlist.add("E"); arrlist.add("F"); arrlist.add("M"); arrlist.add("E"); System.out.println("Size of list: " + arrlist.size()); for (String value : arrlist) { System.out.println("Value = " + ... Read More
The java.util.function.UnaryOperator interface and can be used as assignment target for lambda expressions, it represents operation on a single operand whose result will be of same type as the input. We can create our own UnaryOperator by implementing this interface.The replaceAll() method of the List interface accept an object of the UnaryOperator representing a particular operation performs the specified operation on all the elements of the current list and replaces the existing values with the resultant values.In the following example we are implementing the UnaryOperator interface and creating a custom unary operator object and trying to pass it as an ... Read More
The addAll(int index, Collection
The addAll(Collection
Python tuple is an immutable object. Hence any operation that tries to modify it (like append/insert) is not allowed. However, following workaround can be used.First, convert tuple to list by built-in function list(). You can always append as well as insert an item to list object. Then use another built-in function tuple() to convert this list object back to tuple.>>> T1=(10,50,20,9,40,25,60,30,1,56) >>> L1=list(T1) >>> L1 [10, 50, 20, 9, 40, 25, 60, 30, 1, 56] >>> L1.append(100) >>> L1.insert(4,45) >>> T1=tuple(L1) >>> T1 (10, 50, 20, 9, 45, 40, 25, 60, 30, 1, 56, 100)
Slicing operator can be used with any sequence data type, including Tuple. Slicing means separating a part of a sequence, here a tuple. The symbol used for slicing is ‘:’. The operator requires two operands. First operand is the index of starting element of slice, and second is index of last element in slice+1. Resultant slice is also a tuple.>>> T1=(10,50,20,9,40,25,60,30,1,56) >>> T1[2:4] (20, 9)Both operands are optional. If first operand is missing, slice starts from beginning. If second operand is missing, slice goes upto end.>>> T1=(10,50,20,9,40,25,60,30,1,56) >>> T1[6:] (60, 30, 1, 56) >>> T1[:4] (10, 50, 20, 9)
By definition, tuple object is immutable. Hence it is not possible to remove element from it. However, a workaround would be convert tuple to a list, remove desired element from list and convert it back to a tuple.>>> T1=(1,2,3,4) >>> L1=list(T1) >>> L1.pop(0) 1 >>> L1 [2, 3, 4] >>> T1=tuple(L1) >>> T1 (2, 3, 4)
The built-in function tuple() converts a Python string into tuple of individual characters. It also turns a list object into a tuple.>>> tuple("TutorialsPoint") ('T', 'u', 't', 'o', 'r', 'i', 'a', 'l', 's', 'P', 'o', 'i', 'n', 't') >>> L1=[45, 32, 100, 10, 24, 56] >>> tuple(L1) (45, 32, 100, 10, 24, 56)
Position of an element in a list (any sequence data type for that matter) is obtained by index() method. This method finds first instance of occurrence of given element.>>> L1=[45, 32, 100, 10, 24, 56] >>> L1.index(24) 4