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Suppose we have an array of n elements. Some elements appear twice and other appear once. Elements are in range 1 0, then add i + 1 into the answerreturn the answerExampleLet us see the following implementation to get better understanding − Live Demo#include using namespace std; void print_vector(vector v){ cout
Suppose we have two arrays A and B, there are few elements in these array. We have to find the intersection of them. So if A = [1, 4, 5, 3, 6], and B = [2, 3, 5, 7, 9], then intersection will be [3, 5]To solve this, we will follow these steps −Take two arrays A and Bif length of A is smaller than length of B, then swap themcalculate the frequency of elements in the array and store them into mfor each element e in B, if e is present in m, and frequency is non-zero, decrease frequency ... Read More
Suppose we have a lowercase string. Our task is to reverse the vowels present in the string. So if the string is “hello”, then the string after vowel reversal will be “holle”. For string “programming”, it will be “prigrammong”To solve this, we will follow these steps −Take the string and make a list of vowels, and store their indices as wellreverse the vowel listset idx := 0for i := 0 to length of given string – 1if i is in index list −put vowels[i] into final stringidx := idx + 1otherwise put string[i] into final stringreturn the list as a ... Read More
Suppose in a company, one product manager is leading a team who develops a new product. Suppose latest version fails the quality check. Since each version is developed based on the previous version, all the versions after a bad version will be bad. So we have an array A with n elements [1, 2, … n] and we have to find the first bad version from this array.Consider we have a function isBadVersion(version_id), this will return whether the version is bad or not. For an example, suppose n = 5, and version = 4 is first bad version. So if ... Read More
Suppose we have a binary search tree. we have to find the Lowest common ancestor nodes of two given nodes. The LCA of two nodes p and q is actually as the lowest node in tree that has both p and q as decedent. So if the binary tree is like [6, 2, 8, 0, 4, 7, 9, null, null, 3, 5]. The tree will be like −Here LCA of 2 and 8 is 6To solve this, we will follow these steps −If the tree is empty, then return nullif p and q both are same as root, then return ... Read More
Here we will see how to detect a number n is one Happy number or not. So the happy number is a number, where starting with any positive integers replace the number by the sum of squares of its digits, this process will be repeated until it becomes 1, otherwise it will loop endlessly in a cycle. Those numbers, when the 1 has found, they will be happy number.Suppose the number is 19, the output will be true as the number is happy number. As we can see from 19, we will get12 + 92 = 8282 + 22 = ... Read More
Suppose we have one unsigned number x, and we can easily find the binary representation of it (32bit unsigned integer). Our task is to reverse the bits. So if the binary representation is like 00000000000000000000001001110100, then reversed bits will be 00101110010000000000000000000000. So we have to return the actual number after reversing the bitsTo solve this, we will follow these steps −Suppose n is the given numberlet answer := 0for i := 31 down to 0:answer := answer OR (n AND i), and shift it to the left i timesn := n after right shifting 1 bitreturn answerExampleLet us see the ... Read More
Suppose we have two linked lists A and B, there are few elements in these linked lists. We have to return the reference of the intersection points. The inputs are intersectionVal = 8, A = [4, 1, 8, 4, 5], B = [5, 0, 1, 8, 4, 5], skipA = 2 and skipB = 3, these are used to skip 2 elements from A and skip 3 elements from B.To solve this, we will follow these steps −Define a map called dwhile headA is not nulld[headA] := 1headA := next of headAwhile headB is not nullif headB in dreturn headBheadB ... Read More
Suppose we have one binary tree. We have to check whether the tree is a symmetric tree or not. A tree will be said to be symmetric if it is the same when we take the mirror image of it. From these two trees, the first one is symmetric, but the second one is not.To solve this, we will follow these steps.We will call following steps recursively. The function will be solve(root, root)if the node1 and node2 are empty, then return trueif either node1 or node2 is empty, then return falsereturn true when node1.val = node2.val and solve(node1.left, node2.right) and ... Read More
Suppose we have two sorted arrays A and B. We have to merge them and form only one sorted array C. The size of lists may different.For an example, suppose A = [1, 2, 4, 7] and B = [1, 3, 4, 5, 6, 8], then merged list C will be [1, 1, 2, 3, 4, 4, 5, 6, 7, 8]To solve this, follow these steps −define i := 0, j := 0 and end := length of A – 1while end >= 0 and not A[end], end := end – 1while j < length of Bif i > end ... Read More