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Suppose we have a Binary Search Tree, we have to convert it into a Greater Tree such that every key of the original BST is changed to the original key + sum of all keys greater than the original key in BST.So, if the input is likethen the output will beTo solve this, we will follow these steps −Define a function revInorder(), this will take tree root and s, if root is null, then −returnrevInorder(right of root, s)s := s + val of rootval of root := srevInorder(left of root, s)From the main method, do the following −if root is ... Read More
The different methods of creating a css expression are listed below −Using a class as css selectorThis will select all the web elements of that particular class. (Represented by (.) for example - .classname)Using an id as css selector.This will select the web element of that particular id. (Represented by (#) for example - #ID)Using a tagname and attribute value as selector.This will select the web element of that particular attribute value combination. (Represented by tagname [attribute=’value’])Exampleimport org.openqa.selenium.By; import org.openqa.selenium.Keys; import org.openqa.selenium.WebDriver; import org.openqa.selenium.WebElement; import org.openqa.selenium.chrome.ChromeDriver; import java.util.concurrent.TimeUnit; public class CssExpression { public static void main(String[] args) { ... Read More
We can identify the nth sub element using xpath in the following ways −By adding square brackets with index.By using position () method in xpath.Exampleimport org.openqa.selenium.By; import org.openqa.selenium.Keys; import org.openqa.selenium.WebDriver; import org.openqa.selenium.WebElement; import org.openqa.selenium.chrome.ChromeDriver; import java.util.concurrent.TimeUnit; public class SubElement { public static void main(String[] args) { System.setProperty("webdriver.chrome.driver", "C:\Users\ghs6kor\Desktop\Java\chromedriver.exe"); WebDriver driver = new ChromeDriver(); String url = "https://www.tutorialspoint.com/index.htm"; driver.get(url); driver.manage().window().maximize(); driver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS); // xpath using position() targeting the first element with type text driver.findElement(By.xpath("//input[@type='text'][position()=1]")) ... Read More
Suppose we have an array and an integer k, we have to find the number of unique k-diff pairs in the array. Here the k-diff pair is like (i, j), where i and j are both are present in the array and their absolute difference is k.So, if the input is like [3, 1, 4, 1, 5], k = 2, then the output will be 2, as there are two 2-diff pairs in the array-like (1, 3) and (3, 5).To solve this, we will follow these steps −Define maps called seen and doneDefine one set sif k < 0, then ... Read More
Suppose we have two strings; we have to find the longest uncommon subsequence of these two strings. The longest uncommon subsequence is actually the longest subsequence of one string and this subsequence should not come in the other string. So, we have to find the length of the longest uncommon subsequence. If the longest uncommon subsequence doesn't exist, return -1.So, if the input is like "aabbac", "aabbcc", then the output will be 6To solve this, we will follow these steps −if a is same as b, then −return -1Otherwisereturn maximum of size of a and size of bExample Let us see ... Read More
Each of the locators has some significance. If the page contains uniqueattribute values, we should use them first. However if there are no unique elements, we should use css selector as it is more effective in terms of speed.Css also has a drawback that we cannot traverse from child to parent node which means we cannot travel backward. But xpath allows this feature. Xpath is the most common locator in Selenium and performs traversal through DOM elements and attributes to identify an object.An xpath is represented by two ways namely ‘/ ‘and ‘// ‘. A forward single slash means absolute ... Read More
Suppose we have to check whether a given number is perfect number or not. A number is said to be a Perfect Number when that is equal to the sum of all its positive divisors except itself. The number n will be in range 1^8.So, if the input is like 28, then the output will be True, as its sum of divisors − 1 + 2 + 4 + 7+ 14 = 28.To solve this, we will follow these steps −As the numbers are in range 10^8, there are only few perfect numbers, if the given input is in that ... Read More
Suppose we have a list of scores of N athletes, we have to find their relative ranks and the people with the top three highest scores, who will be different medals: "Gold", "Silver" and "Bronze".So, if the input is like [2, 5, 3, 1, 0], then the output will be [Bronze, Gold, Silver, 4, 5]To solve this, we will follow these steps −if size of nums is same as 1, then −return "Gold"if size of nums is same as 2, then −if nums[0] > nums[1], then −return "Gold", "Silver"Otherwisereturn "Silver", "Gold"Define an array vDDefine an array vecfor initialize i := ... Read More
Given a list of words, we have to find those words that can be typed using letters of the alphabet on only one row's of standard keyboard layout.So, if the input is like ["hello", "world", "mom", "dad", "try", "type", "tom"], then the output will be ["dad", "try", "type"]To solve this, we will follow these steps −Define an array outputoneRow := trueDefine one map charToRowMap, this will take all pairs such that {letter, line}, the letter is the letter present on the keyboard, and line is the line number on the keyboard.for each word in words array −if the word is ... Read More
To identify elements based on text visible on page, text() method is used in xpath.Syntax −driver.findElement(By.xpath("//tagname[text()=’value’]"))Exampleimport org.openqa.selenium.By; import org.openqa.selenium.Keys; import org.openqa.selenium.WebDriver; import org.openqa.selenium.WebElement; import org.openqa.selenium.chrome.ChromeDriver; import java.util.concurrent.TimeUnit; public class TextMatch { public static void main(String[] args) { System.setProperty("webdriver.chrome.driver", "C:\Users\ghs6kor\Desktop\Java\chromedriver.exe"); WebDriver driver = new ChromeDriver(); String url = "https://www.tutorialspoint.com/index.htm"; driver.get(url); driver.manage().window().maximize(); driver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS); //xpath with text() method driver.findElement(By.xpath("//*[text()=’GATE Exams’]")).click(); driver.close(); } }Read More